Lets look at another aspect of this, a bit into functional programming, where the principle is everything is a function. Now, lets look at the topic of this article, managing FizzBuzz based on rules, such that you can modify it without changing it. This is resolved by using print(“Fizz”, terminator: “”) Rule based This is easily resolved with using the terminator as “” instead of the default ‘ ’.

There are still little differences where ‘FizzBuzz’ instead of being printed as one for 15, it prints Fizz and Buzz on each line. So what you are basically doing is dividing the current number with 3 or 5, if it is completely divisible, then you say Fizz if it is a multiple of 3, Buzz if it is a multiple of 5 and in Special cases where it is a multiple of 15 (3 and 5), like 15, 30, 45, 60, 75, 90 you say FizzBuzz. The reasoning behind this problem is to check if you can use the Modulus operator. Here’s how a typical game would go… where 3=Fizz, and 5=Buzz 1, 2, Fizz, 4, Buzz, Fizz, 7, 8, Fizz, Buzz, 11, Fizz, 13, 14, FizzBuzz.

However, the tricky part is not to say certain numbers of multiples of those numbers. It is based on a childhood game (I knew of a variant, not FizzBuzz) the idea is simple, you stand in a circle (or facing each other if you are just two), and you say a number, the others say the next number and so on. No, it is not to do with long term storage of your open cola bottle. If you have interviewed at any point recently, then you might have come across the FizzBuzz problem.

Is fizz buzz drinking game